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3s^2-30s-600=0
a = 3; b = -30; c = -600;
Δ = b2-4ac
Δ = -302-4·3·(-600)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-90}{2*3}=\frac{-60}{6} =-10 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+90}{2*3}=\frac{120}{6} =20 $
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